highaltitude.log.20090913

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[00:03] <Laurenceb> http://pastebin.com/m4ef2915b
[00:03] <Laurenceb> thats my rocket code, its a mess but may be useful
[00:03] <natrium42> hawt
[00:06] <Laurenceb> aerolab is limited to mach 8 so I approximated the Cd/mach curve with an exponential decay
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[00:10] <edmoore> natrium42: yo sorry
[00:10] <natrium42> sup?
[00:13] <edmoore> i haves a favour to ask
[00:13] <edmoore> for my memory and that
[00:13] <edmoore> you remember that lameduck download for crossover for mac?
[00:14] <natrium42> yah
[00:14] <edmoore> it was given away for free if george bush did something-or-other
[00:14] <edmoore> I have lost my dmg that i downloaded, but i def sent some other people a copy, but can't remember who. were you a recipient?
[00:15] <natrium42> i don't think so
[00:15] <natrium42> i requested two copies from them
[00:15] <natrium42> i found the emails
[00:16] <natrium42> but not sure where i saved the dmg
[00:16] <edmoore> ok not to worry. will keep looking
[00:16] <natrium42> sorry :S
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[06:38] <rjharrison_> yo natrium42 you still up?
[06:38] <natrium42> hi
[06:38] <rjharrison_> I was wondering what the crossovewr did
[06:38] <rjharrison_> I think I have managed to pull a copy for ed
[06:38] <rjharrison_> Is it something that you might be interested in?
[06:39] <rjharrison_> dmg mac
[06:41] <natrium42> it's a windows api layer for unis
[06:41] <natrium42> *unix
[06:44] <rjharrison_> Oh well if you want it let me know
[06:44] <rjharrison_> oh you have it may how
[06:45] <rjharrison_> any
[06:46] <natrium42> i just use wine
[06:46] <natrium42> it's free
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[10:29] <ShellEvil> free as in wine
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[17:25] <sbasuita> Maths question for you guys: If I have a set of depth measurements and a total width for the cross section of a (real, not ideal) river, what would be the easiest method to work out the cross sectional area (as oppposed to drawing a graph and counting squares)?
[17:32] <SpeedEvil> First - assume a spherical river.
[17:32] <SpeedEvil> More seriously.
[17:32] <SpeedEvil> You have a segment of width x, with depths y1, and y2 at the edges.
[17:33] <SpeedEvil> If we assume that the bottom edge is straight
[17:33] <SpeedEvil> that gives x*((y1+y2)/2)
[17:33] <SpeedEvil> for the area
[17:34] <SpeedEvil> - you simply multiply the width by the average depth
[17:34] <SpeedEvil> now - you do this for all strips of x,y pairs you have
[17:34] <SpeedEvil> and simply add
[17:35] <sbasuita> SpeedEvil, ok, so integration from first principles. That's cool. BTW, I assume there are methods for finding an 'approximate' equation to describe the line of the river bed?
[17:36] <SpeedEvil> Yes.
[17:36] <SpeedEvil> You can for example treat it as a fourier problem
[17:37] <SpeedEvil> that gives you the answer in terms of sinewaves of various frequencies added
[17:37] <SpeedEvil> Or polynomial fit
[17:37] <SpeedEvil> These all fall into the category of making shit up.
[17:38] <SpeedEvil> As the only actual data you have is the points - however pretty the resultant function is.
[17:38] <sbasuita> Hehe, thanks for the help SpeedEvil.
[17:38] <SpeedEvil> np
[17:38] <SpeedEvil> This is actually a problem with digital scopes
[17:38] <SpeedEvil> The real 'measurement' that you're taking may be from 10 samples.
[17:39] <SpeedEvil> But the scope nicely extrapolates this to a lovely smooth curve that might even be close to the truth.
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[19:50] <gordonjcp> http://science.slashdot.org/article.pl?sid=09/09/13/1712216
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[20:02] <forrestv> where is Laurenceb :(
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[22:17] <rjharrison_> Goodnight all
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[00:00] --- Mon Sep 14 2009